Hello so when you unscrew or try to unscrew the pivot axel it's pushing the drive side away from the bike? They way the axel is designed is it tightens up into the drive side and then bottoms out on the bearing(and seals) on the non drive side what hold the no drive side is a taper lock. I presume when you tried to take the axel out you had the taper lock yoke out ( I can't remember if the Allen key for main axel will fit through the taper lock cone.)It sound like your right to stop if you encountered resistance. If you back it off and when the drive side is pushing away give a thump with your palm. I bet the issue is the taper lock is still locked which is blue below. The chain stay pushing away can only be that. Hope this helps
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Yep, the taper lock is out and the Allen key is in the Main pivot axle. It winds out perhaps 3 or 4 turns perfectly (visible on both sides). It’s simply pushing the non drive side in and pushing the drive side out and on the non drive side it then interferes with the frame.